A spiral heat exchanger
The basic heat exchanger design equation,
Q = U A ?Tlm,
was introduced and discussed in another article, “Fundamentals of Heat Exchanger Theory and Design.” When used as a design equation to calculate the required heat transfer surface area, the equation can be rearranged to become :
A = Q/(U ?Tlm),
where Q is the required heat transfer rate in Btu/hr, U is the overall heat transfer coefficient in Btu/hr-oF, and ?tlm is the log mean temperature difference in oF.
Design of heat exchangers is an iterative (trial & error) process. Here is a set of steps for the process
Calculate the required heat transfer rate, Q, in Btu/hr from specified information about fluid flow rates and temperatures.
Make an initial estimate of the overall heat transfer coefficient, U, based on the fluids involved.
Calculate the log mean temperature difference, ?Tlm, from the inlet and outlet temperatures of the two fluids.
Calculate the estimated heat transfer area required, using : A = Q/(U ?Tlm).
Select a preliminary heat exchanger configuration.
Make a more detailed estimate of the overall heat transfer coefficient, U, based on the preliminary heat exchanger configuration.
Estimate the pressure drop across the heat exchanger. If it is too high, revise the heat exhcanger configuration until the pressure drop is acceptable.
If the new estimate of U is significantly different than the previous estimate, repeat steps 4 through 7 as many times as necessary until the two estimates are the same to the desired degree of accuracy.
In order to start the heat exchanger design process, several items of information are needed as follows :
Knowing the first four items allows determination of the required heat transfer rate, Q, and the inlet and outlet temperatures of both fluids, thus allowing calculation of the log mean temperature difference, ?Tlm. With values now available for Q, U, and ?Tlm, an initial estimate for the required heat transfer area can be calculated from the equation,
A = Q/(U ?Tlm).
Example #1 : Calculate a preliminary estimate of the heat exchanger area needed to cool 55,000 lb/hr of a light oil (specific heat = 0.74 Btu/lb-oF) from 190oF to 140oF using cooling water that is available at 50oF. The cooling water can be allowed to heat to 90oF. An initial estimate of the overall heat transfer coefficient is 120 Btu/hr-ft2–oF. Also estimate the required mass flow rate of cooling water.
Solution : First calculate the required heat transfer rate based on the required light oil cooling :
Q = (55,000 lb/hr)(0.74 Btu/lb-oF)(190 – 140)oF = 2,035,000 Btu/hr.
Next calculate the log mean temperature difference :
?Tlm = [(190 – 90) – (140 – 50)]/ln[(190 – 90)/(140 – 50)] = 94.9oF
The preliminary area estimate can now be calculated as :
A = Q/(U ?Tlm) = 2,035,000/(120)(79.58) = 178.7 ft2 = A
The required mass flow rate of water can be calculated from Q = m Cp ?T.
Rearranging : m = Q/Cp ?T = (2,035,000 Btu/hr)/(1 Btu/lb-oF)(40oF) = 50,875 lb/hr
Example #2: A shell and tube heat exchanger is to be used for the light oil cooling described in Example #1. How many tubes of 3 inch diameter and 10 ft length should be used?
Solution : The surface area per tube will be ?DL = ?(3/12)(10) ft2 = 7.854 ft2. The number of tubes required would thus be :
n = 178.7 ft2/7.854 ft2/tube = 22.7 tubes (round up to 23 tubes).
The next step would be to check on the pressure drop for this tube configuration and the specified flow. If the pressure drop is acceptable, then the overall heat transfer coefficient could be re-estimated for this heat exchanger configuration. These topics will be dealt with in a future article.
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